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Old 09-23-2006, 05:57 PM   #1
tw
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How can this (math) be?

How can this be?

Assume that:
a = b
Therefore:
a^2 = ab
a^2 - b^2 = ab - b^2
(a+b)(a-b) = b (a-b)
a+b = b
Since a = b then
2*b = b
2 = 1

The riddle (a mathematical joke) was provided by EE Times. Yes, a simple algebraic flaw exists. But what is it?
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Old 09-23-2006, 06:04 PM   #2
vrai_rennx
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This is totally going to bug the crap out of me until I figure it out... But I worked it out and I can't find the mistake... Ah, my math teachers sucked.
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Old 09-23-2006, 06:27 PM   #3
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Quote:
Originally Posted by tw
a^2 - b^2 = ab - b^2
a^2 - b^2 = 0. Game over.
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Old 09-23-2006, 06:55 PM   #4
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Not quite - the problem is that (a-b) is zero, and you are dividing by it in step 3 to 4.
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Old 09-23-2006, 09:28 PM   #5
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Quote:
Originally Posted by tw
(a+b)(a-b) = b (a-b)
a+b = b
To get from (a+b)(a-b) = b (a-b)
to
a+b = b
you must divide each side by (a-b). That's great, except...

since a=b, then (a-b) = (a-a) = 0

Only Chuck Norris can divide by zero.
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Old 09-23-2006, 09:36 PM   #6
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Quote:
Originally Posted by Happy Monkey
Not quite - the problem is that (a-b) is zero, and you are dividing by it in step 3 to 4.
If a = b then a^2 - b^2 = ab - b^2 is the same thing as saying 0 = 0. I think you are done at that point.
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Old 09-23-2006, 10:21 PM   #7
lumberjim
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i contemplated just posting 'pull my finger' here, but instead, my curiosity has me. .....


what does '^' mean in math?
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Old 09-23-2006, 10:33 PM   #8
Beestie
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^ means raise to the power of. So a^2 means a squared and a^3 means a*a*a.
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Old 09-23-2006, 10:43 PM   #9
lumberjim
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thank you. now.....pull my finger
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Old 09-23-2006, 11:28 PM   #10
mbpark
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Algebra 1

Doesn't anyone remember FOIL?

(a+b)(a-b) = b (a-b)
a^2 -ab + ab -b^b
a^2 - b^2
0

Therefore, 2 does not equal 1
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Old 09-23-2006, 11:36 PM   #11
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RIght, the whole thing hinges on one '0=0' set after another. They sneak in a '2*0=0' and try to equate it with 2*1=1, the mistake is in the very last operation.
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Old 09-24-2006, 02:29 AM   #12
wolf
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You divide by zero to get from step three to four, don't you?

My junior high Algebra teacher showed us this.
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Old 09-24-2006, 09:38 AM   #13
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Quote:
Originally Posted by wolf
You divide by zero to get from step three to four, don't you?
Yes, but I think (and I could be wrong, it's been awhile since I was in junior high myself) it's okay, because you're dividing zero by zero, and 0/0 is the one acceptable case where it equals one.
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Old 09-24-2006, 09:42 AM   #14
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You can't do that either... there's no definite value for it.
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Old 09-24-2006, 12:41 PM   #15
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Quote:
Originally Posted by Beestie
If a = b then a^2 - b^2 = ab - b^2 is the same thing as saying 0 = 0. I think you are done at that point.
No. 0=0 is OK, just like 1=1 is OK in step one. You just can't divide by zero.
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