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03-18-2010, 09:22 PM | #1 |
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Math Homework Help for 8th Grader
Got a problem to solve. I worked on this with my daughter last night, and I got an answer, but apparently I'm wrong!
There are six busybodies in town who like to share information. Whenever one of them calls another, they both know everything that the other one knew by the end of the conversation. One day, each of the six women picks up a juicy piece of gossip. What is the minimum number of phone calls required before all six of them know all six of these tidbits? I got 10, but I guess it's not right! Help? |
03-18-2010, 10:42 PM | #2 |
UNDER CONDITIONAL MITIGATION
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10's the best I got, sorry.
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03-18-2010, 10:45 PM | #3 |
~~Life is either a daring adventure or nothing.~~
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It's the worst problem ever. 5, no 3 no....oh I don't know.
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03-18-2010, 10:51 PM | #4 |
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I got nine.
ABC DEF B calls A and C (2) E calls D and F (2) B calls E (1) B calls A and C (2) E calls D and F (2) Total: 9
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03-18-2010, 11:15 PM | #5 |
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I think I got 8.
Each caller is a letter and each number is a bit of gossip. A B C D E F 1 2 3 4 5 6 A calls F (A has 1,6 F has 1,6) B calls E (B has 2,5 E has 2,5) C calls D (C has 3,4 D has 3,4) A calls E (A has 1,2,5,6 E has 1,2,5,6) A calls D (A has 1,2,3,4,5,6 D has 1,2,3,4,5,6) A calls B (A has 1,2,3,4,5,6 B has 1,2,3,4,5,6) C calls E (C has 1,2,3,4,5,6 E has 1,2,3,4,5,6) E calls F (E has 1,2,3,4,5,6 F has 1,2,3,4,5,6)
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03-18-2010, 11:33 PM | #6 |
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I had amended my answer to 9 also, but I think Squirrel's right!
Thanks! Every quarter daughter gets these "critical thinking" worksheets for math - things like the family crossing the river in a boat that can only hold two, the frogs and lily pads, various puzzles . . . and for us non-math types, they are HARD!!! |
03-19-2010, 12:31 AM | #7 |
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If a hen and a half can lay an egg and a half in a day and a half, how long does it take a cricket with a wooden leg to kick all the seeds from a dill pickle?
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03-19-2010, 02:33 AM | #8 |
I'm still a jerk
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an infinite amount of time
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03-19-2010, 10:26 AM | #9 |
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You get partial Credit. It takes half as long as it takes for an elephant with a wooden leg to bore a hole in a bar of soap.
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03-19-2010, 10:40 AM | #10 | |
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Quote:
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The most difficult thing is the decision to act, the rest is merely tenacity Amelia Earhart |
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03-19-2010, 11:48 AM | #11 |
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No two card shuffles will ever be the same.
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****************** There's a level of facility that everyone needs to accomplish, and from there it's a matter of deciding for yourself how important ultra-facility is to your expression. ... I found, like Joseph Campbell said, if you just follow whatever gives you a little joy or excitement or awe, then you're on the right track. . . . . . . . . . . . . . . . . . . . . . . . . . . Terry Bozzio |
03-19-2010, 12:01 PM | #12 |
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but strangely, two flint posts can be, despite the fact that the number of possible word/idea combinations in that head must outstrip the number of possible card shuffles.
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The most difficult thing is the decision to act, the rest is merely tenacity Amelia Earhart |
03-19-2010, 02:01 PM | #13 |
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03-19-2010, 02:22 PM | #14 |
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Mathematical closed form solution: in this example, k=2, n=6.
f(n,k)=2[(n−k)(k−1)] =2[(4)(1)] = 8 Squirrel for the win! ETA, Juni, this is neither a trivial or a simple problem. Kudos to your kid's math teacher!
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per·son \ˈpər-sən\ (noun) - an ephemeral collection of small, irrational decisions The fun thing about evolution (and science in general) is that it happens whether you believe in it or not. |
03-19-2010, 02:34 PM | #15 |
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Interesting that ONR is supporting this research. Network topology is still a hot topic!
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per·son \ˈpər-sən\ (noun) - an ephemeral collection of small, irrational decisions The fun thing about evolution (and science in general) is that it happens whether you believe in it or not. |
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